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Sagot :
The unknown gas : N₂
Further explanation
Given
Volume : 23.1 L
Mass : 28.85 g
Required
The identity of the unknown gas
Solution
Conditions at T 0 ° C and P 1 atm are stated by STP (Standard Temperature and Pressure). At STP, Vm is 22.4 liters / mol
So mol for The unknown gas :
= 23.1 L : 22.4 L
= 1.0313
The molar mass of unknown gas :
= mass : mol
= 28.85 g : 1.0313
= 27.974 g/mol≈ 28 g/mol
23.1 L of nitrogen has a mass of 28.85 g at STP.
An unknown gas occupies 23.1 L at STP. We will calculate the moles of the gas, considering that 1 mole of an ideal gas occupies 22.4 L at STP.
[tex]23.1 L \times \frac{1mol}{22.4L} = 1.03 mol[/tex]
1.03 moles of the unknown gas have a mass of 28.85 g. The molar mass of the gas is:
[tex]M = \frac{28.85 g}{1.03 mol} = 28.0 g/mol[/tex]
A gas with a molar mass of 28.0 g/mol is likely to be nitrogen gas.
23.1 L of nitrogen has a mass of 28.85 g at STP.
Learn more: https://brainly.com/question/4172228
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