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What is the equation of the horizontal line that contains the point (3,−8)?

Sagot :

absor201

Answer:

The equation of the horizontal line that contains the point (3,−8) will be:

  • y = -8

Step-by-step explanation:

The slope-intercept form of the line equation

y = mx+b

where

  • m is the slope
  • b is the y-intercept

We need to determine the equation of the horizontal line that contains the point (3, −8).

We know that the slope of a horizontal line m = 0

Thus, in our case:

  • Slope m = 0
  • Point (3, -8)

now substituting m = 0 and the point (3, -8) in the slope-intercept form of the line equation to determine the y-intercept

y = mx+b

-8 = 0(3) + b

-8 = 0 + b

b = -8

Thus, the y-intercept b = -8

now substituting m = 0 and b = -8  in the slope-intercept form of the line equation

y = mx+b

y = 0(x) + (-8)

y = 0 - 8

y = -8

Therefore, the equation of the horizontal line that contains the point (3,−8) will be:

  • y = -8

Please also check the attached graph below.

View image absor201
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