Answered

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- 3x + 4 and passes through the point (2,5)
Write the equation of a line that is perpendicular to the equation y =

Sagot :

theintel

Answer:

y=(x+13)/3

Step-by-step explanation:

the question is not quite clear, i think u mean y= -3x + 4

then, the slope of the line perpendicular to the given line is m1.m2= -1, hence, -3.m2= -1 m2 = 1/3

y-5=1/3(x-2) y=x/3+13/3 or y=(x+13)/3

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