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The formula B=10log(i/i0) is used to find the sound level, , in decibels (dB), of a sound with an intensity of I. In the formula, represents the smallest sound intensity that can be heard by the human ear (approximately ).

What is the sound intensity of a noise that is 130 dB?

The sound intensity is
.


The Formula B10logii0 Is Used To Find The Sound Level In Decibels DB Of A Sound With An Intensity Of I In The Formula Represents The Smallest Sound Intensity Th class=

Sagot :

Answer:

The Answer is 10 watts/meter^2.

Step-by-step explanation:

Substitute 130 for B.

Substitute 10^-12 for i0.

I am not going to write absolutly everything because I would be here for days lol

The sound intensity is 10 watts/meter^2.

We have given that the formula

[tex]B=10log(I/I_0)[/tex]

We have B=130

Substitute 130 for B.

[tex]I_0[/tex] is the intensity that can be heard by human ear and that is

[tex]10^{-12} Watt/m^2[/tex]

Substitute 10^-12 for [tex]I_o[/tex]

[tex]130=10log(I/10^{-12} )\\10\log _{10}\left(\frac{I}{10^{-12}}\right)=130[/tex]

divide both side by 10

[tex]\frac{10\log _{10}\left(\frac{I}{10^{-12}}\right)}{10}=\frac{130}{10}[/tex]

[tex]\log _{10}\left(\frac{I}{10^{-12}}\right)=13[/tex]

Which log rule we use here?

[tex]log_{e}a=C \implies a=e^{C}[/tex]

Therefore, we get

[tex]\frac{I}{10^{-12}}=10^{13}[/tex]

[tex]I\times10^{12}=10^{13}\\I=10[/tex]

Therefore the sound intensity is 10 watts/meter^2.

To learn more about the sound intensity visit:

https://brainly.com/question/17062836