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Sagot :
The car experienced the force for about 1.08 secs
From Newton's second law of motion,
Force is directly proportional to the rate of change of momentum
That is,
[tex]F = \frac{m(v-u)}{t}[/tex]
Where F is the force
m is the mass
v is the final velocity
u is the initial velocity
and t is time
Then,
The Impulse of the force (Ft) is equal to change in momentum m(v-u)
That is,
[tex]Ft = m(v-u)[/tex]
From the question,
Mass of the car, m = 1279 kg
Initial velocity, u = 26.82 m/s
Force = -20000 N
(NOTE: The force is negative because, it is acting in the opposite direction)
Final velocity, v = 10 m/s
To determine the how long the car experienced the force, we will put the above parameters into the equation
[tex]Ft = m(v-u)[/tex]
Then,
[tex]-20000 \times t=1279(10-26.82)[/tex]
[tex]-20000 t=1279(-16.82)[/tex]
[tex]-20000 t=-21512.78[/tex]
Now, divide both sides by -20000
[tex]\frac{-20000 t}{-20000} = \frac{-21512.78}{-20000}[/tex]
[tex]t = 1.08 \ secs[/tex]
Hence, the car experienced the force for about 1.08 secs
Learn more here: https://brainly.com/question/24589431
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