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Sagot :
Answer: 3.45 L carbon dioxide are produced
Explanation:
According to avogadro's law, 1 mole of every substance occupies 22.4 L at STP and contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given volume}}{\text {Molar volume}}=\frac{5.75L}{22.4L}=0.257moles[/tex]
[tex]C_3H_8+5O_2(g)\rightarrow 3CO_2+4H_2O[/tex]
According to stoichiometry :
5 moles of [tex]O_2[/tex] produce = 3 moles of [tex]CO_2[/tex]
Thus 0.257 moles of [tex]O_2[/tex] will produce=[tex]\frac{3}{5}\times 0.257=0.154moles[/tex] of [tex]CO_2[/tex]
Volume of [tex]CO_2=moles\times {\text {Molar volume}}=0.154moles\times 22.4L/mol=3.45[/tex]
Thus 3.45 L carbon dioxide are produced
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