Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Join our platform to connect with experts ready to provide precise answers to your questions in different areas. Get detailed and accurate answers to your questions from a dedicated community of experts on our Q&A platform.
Sagot :
Answer:
Oxygen.
Explanation:
Hello!
In this case, since the ideal gas equation allows us to compute the moles of oxygen in 5.60 L at STP (1 atm and 273.15 K) as shown below:
[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{1atm*5.60L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n_{O_2}= 0.25mol[/tex]
Next, given the molar mass of carbon dioxide (44.01 g/mol) we compute the moles in 10.0g of this gas via:
[tex]n_{CO_2}=10.0gCO_2*\frac{1molCO_2}{44.01gCO_2} =0.23molCO_2[/tex]
Thus, since oxygen has the greatest number of moles, we immediately infer it also has the greatest number of molecules based on the Avogadro's number.
Best regards!
Thanks for using our platform. We aim to provide accurate and up-to-date answers to all your queries. Come back soon. Thank you for your visit. We're dedicated to helping you find the information you need, whenever you need it. Get the answers you need at Westonci.ca. Stay informed by returning for our latest expert advice.