Answered

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Which contains more molecules? 10.0 g of CO2 or 5.60L of oxygen gas at STP

Sagot :

sebassandin

Answer:

Oxygen.

Explanation:

Hello!

In this case, since the ideal gas equation allows us to compute the moles of oxygen in 5.60 L at STP (1 atm and 273.15 K) as shown below:

[tex]PV=nRT\\\\n=\frac{PV}{RT}=\frac{1atm*5.60L}{0.08206\frac{atm*L}{mol*K}*273.15K}\\\\n_{O_2}= 0.25mol[/tex]

Next, given the molar mass of carbon dioxide (44.01 g/mol) we compute the moles in 10.0g of this gas via:

[tex]n_{CO_2}=10.0gCO_2*\frac{1molCO_2}{44.01gCO_2} =0.23molCO_2[/tex]

Thus, since oxygen has the greatest number of moles, we immediately infer it also has the greatest number of molecules based on the Avogadro's number.

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