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Write an equation in point-slope form of the line that passes through the given point and is parallel to the graph of the given equation

Write An Equation In Pointslope Form Of The Line That Passes Through The Given Point And Is Parallel To The Graph Of The Given Equation class=

Sagot :

MrRoyal

Answer:

The equation of the line is:

[tex]y -1= 5(x - 2)[/tex]

Step-by-step explanation:

Given

Pass through [tex](2,-1)[/tex]

Parallel to: [tex]y= 5x - 2[/tex]

Required

Determine the equation in point slope form

An equation has a general form:

[tex]y = mx + c[/tex]

Where:

[tex]m = slope[/tex]

Compare: [tex]y = mx + c[/tex] to [tex]y= 5x - 2[/tex]

we have:

[tex]m = 5[/tex]

Since the line is parallel to [tex]y= 5x - 2[/tex], then they have the same slope of 5

The line equation is then calculated using:

[tex]y -y_1= m(x - x_1)[/tex]

Where

[tex]m = 5[/tex]

[tex](x_1,y_1) =[/tex] [tex](2,-1)[/tex]

So, we have:

[tex]y -1= 5(x - 2)[/tex]

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