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Sagot :

Answer:

∠ BAC ≈ 67.4°

Step-by-step explanation:

Using the sine ratio in the right triangle.

sinA = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{BC}{AB}[/tex] = [tex]\frac{12}{13}[/tex] , then

∠ A = [tex]sin^{-1}[/tex] ([tex]\frac{12}{13}[/tex] ) ≈ 67.4° ( to 1 dec. place )