bcarrera0005
Answered

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how do I solve this?​

How Do I Solve This class=

Sagot :

Answer:

sinJ = [tex]\frac{12}{13}[/tex]

Step-by-step explanation:

sinJ = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{IK}{JK}[/tex] = [tex]\frac{12}{13}[/tex]

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