chiki4
Answered

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Calculate the ratio of change in the mass of the molecules of a gas to the initial mass, if its
speed is reduced to half and the ratio of initial and final pressure is 3:4.

Hint : P =1/3 M/V.v²
​

Sagot :

lucky75

Answer:

Required Answer is as follows :-

  • [tex]\sf \dfrac{P _{i}}{ P_{f}} = \dfrac{3}{4}[/tex]

  • 3/4 = (⅓ × m₁/Volume × V²)/(⅓ × m₂/Volume) × (V/2)²

  • ¾ = m₁/Volume × (V)²/m₂/Volume × (V/2)²

  • ¾ = m₁ × (V)²/m₂ × (V²/4)

  • ¾ = m₁/m₂ × 4

  • m₂ = 4 × 4/3 = 16/3m₁

[tex]\bold{   }[/tex] 

Now,

  • ∆m = m₂ - m₁
  • ∆m = 16m₂/3 - m₁ = 13m₁/3
  • Ratio = (13m₁/3)/ m₁
  • Ratio = 13/3

Ratio = 13:3

[tex]\bold{   }[/tex] 

Know More :-

Mass => It is used to measure it's resistance to its acceleration. SI unit of mass is Kg.[tex]\bold{   }[/tex] 

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