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Can anyone help me?pls

Can Anyone Help Mepls class=

Sagot :

Answer:

41.4°

Step-by-step explanation:

Reference angle = θ

Hypotenuse = 8

Adjacent = 6

Therefore,

[tex] cos(\theta) = \frac{adj}{hyp} [/tex]

[tex] cos(\theta) = \frac{6}{8} [/tex]

[tex] cos(\theta) = 0.75 [/tex]

[tex] \theta = cos^{-1}(0.75) [/tex]

[tex] \theta = 41.4 degrees [/tex] (nearest tenth)