Discover the answers to your questions at Westonci.ca, where experts share their knowledge and insights with you. Explore our Q&A platform to find reliable answers from a wide range of experts in different fields. Connect with a community of professionals ready to help you find accurate solutions to your questions quickly and efficiently.
Sagot :
Given:
[tex]y\propto \dfrac{1}{\sqrt{x}}[/tex]
y = 4 when x = 64
To find:
The value of y when x=16.
Solution:
We have,
[tex]y\propto \dfrac{1}{\sqrt{x}}[/tex]
[tex]y=\dfrac{k}{\sqrt{x}}[/tex] ...(i)
Where, k is the constant of proportionality.
We have, y = 4 when x = 64.
[tex]4=\dfrac{k}{\sqrt{64}}[/tex]
[tex]4=\dfrac{k}{8}[/tex]
[tex]4\times 8=k[/tex]
[tex]32=k[/tex]
Putting k=32 in (i), we get
[tex]y=\dfrac{32}{\sqrt{x}}[/tex]
Putting x=16, we get
[tex]y=\dfrac{32}{\sqrt{16}}[/tex]
[tex]y=\dfrac{32}{4}[/tex]
[tex]y=8[/tex]
Therefore, the value of y is 8 when x=16.
Thanks for stopping by. We are committed to providing the best answers for all your questions. See you again soon. We appreciate your time. Please come back anytime for the latest information and answers to your questions. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.
