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The area of a triangle abc is 4√2 m²

The Area Of A Triangle Abc Is 42 M class=

Sagot :

Answer:

x = 3.08

Step-by-step explanation:

Construct a perpendicular AD from point A to opposite side BC,

By sine ratio,

sin(45)° = [tex]\frac{\text{Opposite side}}{\text{Hypotenuse}}[/tex]

[tex]\frac{1}{\sqrt{2}}= \frac{AD}{(x+2)}[/tex]

AD = [tex]\frac{x+2}{\sqrt{2}}[/tex]

Area of a triangle = [tex]\frac{1}{2}(\text{Base})(\text{Height})[/tex]

                             = [tex]\frac{1}{2}(BC)(AD)[/tex]

[tex]4\sqrt{2}=\frac{1}{2}(2x-3)\frac{(x+2)}{\sqrt{2} }[/tex]

(2x - 3)(x + 2) = 16

2x(x + 2) - 3(x + 2) = 16

2x² + 4x - 3x - 6 = 16

2x² + x - 6 = 16

2x² + x - 22 = 0

By using quadratic formula,

x = [tex]\frac{-1\pm\sqrt{(1)^{2}-4(2)(-22)}}{2(2)}[/tex]

x = [tex]\frac{-1\pm\sqrt{177}}{4}[/tex]

x = 3.076, -3.576

x ≈ 3.08, -3.58

But length of the sides can't be negative

Therefore, x = 3.08 will be the answer.

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