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Elliot spent 3/7 of his money on some comics. He spent 1/4
of the remaining money on a pack of cards.
a) What fraction of Elliot's money has he left?
b) If he has $6 left, how much money did Elliot have at first?


Sagot :

Answer:

a) 3/7

b) $14

Step-by-step explanation:

let the total of his Money be x

on some comics = 3/7 of x

[tex] \frac{3}{7} \times x \: = \frac{3x}{7} [/tex]

remaining money = x - 3x/7

[tex]x - \frac{3x}{7} = \frac{7x - 3x}{7} = \frac{4x}{7} [/tex]

on a pack of cards = 1/4 of 4x/7

[tex] \frac{1}{4} \times \frac{4x}{7} = \frac{4x}{28} = \frac{x}{7} [/tex]

a) left fraction = total money - all spent money

note that; all spent money = money spent on some comics and pack of cards

[tex]x - ( \frac{3x}{7} + \frac{x}{7} )[/tex]

[tex]x - ( \frac{3x + x }{7} )[/tex]

[tex]x - \frac{4x}{7} = \frac{7x - 4x}{7} = \frac{3x}{7} [/tex]

left fraction = 3/7 of the money

b) left money = 3x/7

but since left money is $6

therefore, $6 = 3x/7

multiply both sides by 7

[tex]6 \times 7 = \frac{3x}{7} \times 7[/tex]

42= 3x

divide both sides by 3

x = 42/3

x = 14

total money = $14