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Sagot :
Answer:
The number of molecules of SO₂ gas that would occupy a volume of 4.15 L at STP is 1.1153125 × 10²³ molecules
Step-by-step explanation:
The given parameters for the SO₂ gas are;
The volume of the gas = 4.15 L
The condition of the gas = Standard Temperature, and Pressure, STP
The molar volume = The volume occupied by one mole of a gas at STP = 22.4 L
Therefore, we have;
22.4 L = The volume occupied 1 mole of gas
∴ The number of moles in 1 L of gas = 22.4 L/22.4 of gas = 1/22.4 moles of gas
The number of moles in 4.15 L of gas = 4.15 × 1/22.4 moles = 83/448 moles
∴ The number of moles of SO₂ in 4.15 L of SO₂ = 83/448 moles of SO₂.
The number of molecules in one ole of a substance is given by Avogadro's number, [tex]N_A[/tex] = 6.02 × 10²³ molecules
1 mole of a substance contains 6.02 × 10²³ molecules
83/448 moles of substance contains 83/448 × 6.02 × 10²³ = 1.1153125 × 10²³ molecules
Therefore, the number of molecules in 83/448 moles of SO₂ = 1.1153125 × 10²³ molecules
Therefore, the number of molecules of SO₂ gas that would occupy 4.15 L at STP = 1.1153125 × 10²³ molecules.
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