The yard behind Sandy's house is a rectangle in shape and has a perimeter of
72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what
is the area of the yard, in square feet?
a 36 ft^2
b. 144 ft^2
c. 243 ft^2
d. 486 ft^2

Question

04-02-2021
Mathematics

Answered

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The yard behind Sandy's house is a rectangle in shape and has a perimeter of
72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what
is the area of the yard, in square feet?
a 36 ft^2
b. 144 ft^2
c. 243 ft^2
d. 486 ft^2

Sagot :

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nevaehtaliafero8 nevaehtaliafero8 · Answer 1 · 2021-02-04T09:03:20-05:00

Answer:

Including results for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 x. 243 ft^2 d. 486 ft^2

Search only for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 c. 243 ft^2 d. 486 ft^2

Step-by-step explanation:

Including results for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 x. 243 ft^2 d. 486 ft^2

Search only for 72 feet. If the length 1 of the yard is 18 feet longer than the width w of the yard, what is the area of the yard, in square feet? a 36 ft^2 b. 144 ft^2 c. 243 ft^2 d. 486 ft^2

dammyzee dammyzee · Answer 2 · 2021-02-04T09:10:00-05:00

dammyzee dammyzee

04-02-2021

Answer:

c. 243 ft^2

Step-by-step explanation:

where l = length

w= width

given; l= w+18

perimeter= 2(l+w)

72= 2(l+w)

72/2 = l+w

36= l+w

36= (w+18) +w

36= w+w+18

36= 2w +18

36-18=2w

18=2w

18/2=w

w=9ft

l=w+18

l=9+18= 27ft

Area = l×w

= 27×9 = 243ft^2

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Sagot :

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