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Sagot :
To solve for the hypotenuse or the longest side of the triangle, we can simply use the Pythagorean Theorum.
C^2 = A^2 + B^2
C^2 = (6)^2 + (9)^2
C^2 = 36 + 81
C^2 = 117
C = square root of 117
C = About 10.81 feet
So, in conclusion, the hypotenuse or the longest side of the triangle in feet is: D. Between 10 feet and 11 feet.
C^2 = A^2 + B^2
C^2 = (6)^2 + (9)^2
C^2 = 36 + 81
C^2 = 117
C = square root of 117
C = About 10.81 feet
So, in conclusion, the hypotenuse or the longest side of the triangle in feet is: D. Between 10 feet and 11 feet.
Answer:
D. 10 and 11
Step-by-step explanation:
This problem would use pythagorean theorem because we're finding the hypotenuse of a right triangle. This is its standard equation:
[tex]a {}^{2} + {b}^{2} = {c}^{2} [/tex]
The legs represent [tex]a[/tex] and [tex]b[/tex] respectively, and [tex]c[/tex] represents the hypotenuse. After plugging in the legs' respective values, the equation looks like this:
[tex]6^{2} + {9}^{2} = {c}^{2} →36 + 81 = {c}^{2} →117 = c^{2} [/tex]
To isolate [tex]c[/tex], you would find the square root of [tex]117[/tex]. In this case, we're just finding which integers[tex] \sqrt{117} [/tex] is between. [tex]\sqrt{100}(=10)[/tex] is the closest integer value below [tex]\sqrt{117}[/tex] and [tex]\sqrt{121}(=11)[/tex] is the closest integer value above [tex]\sqrt{117}[/tex]. So the answer is D. 10 and 11.
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