Answered

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How many grams are in 0.002 moles of barium nitrate, Ba(NO3)2

Sagot :

Answer:

0.52 grams

Explanation:

To find the molar mass of Ba(NO3)2, use the periodic table and the mass of each element. Remember to multiply based on the number of atoms there are.

137.33 + [14.01+16(3)] 2 = 261.35

Now solve...

0.002 mol Ba(NO3)2 * 261.35 g Ba(NO3)2/1 mol Ba(NO3)2 = 0.5227

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