katiebrown0041
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The table shows data for a car stopping on a wet road. Stopping distance formula [tex]d(v)=\frac{2.15v^{2} }{64.4f}[/tex]

Determine the value of f, rounded to the nearest hundredth.

The Table Shows Data For A Car Stopping On A Wet Road Stopping Distance Formula Texdvfrac215v2 644ftex Determine The Value Of F Rounded To The Nearest Hundredth class=

Sagot :

Answer:

0.35

the next one is d(v) = 2.15v^2 / 22.54

Step-by-step explanation:

i just did this assignment. also thanks to the answer above me :)

okpalawalter8

We have that the value of f, rounded to the nearest hundredth.

f_1=0.02

f_2=0.009

f_3=0.009

From the question we are told that

d(v)= \frac{2.15v^2}{64.4f}

Generally the equation for the f is mathematically given as

f= \frac{2.15v^2}{64.4*d(v)}

Therefore

For v=20 and f=38

f= \frac{2.15(20)^2}{64.4*(38)(20)}

f=0.02

For v=30 and f=86

f=\frac{2.15(30)^2}{64.4*(86)(30)}

f=0.01

For v=40 and f=153

f=\frac{2.15(40)^2}{64.4*(153)(40)}

f=0.009

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