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In ΔPQR, r = 4.9 cm, ∠R=21° and ∠P=104°. Find the length of p, to the nearest 10th of a centimeter.

Sagot :

38377

Answer:

Step-by-step explanation:

View image 38377

The answer is  the length of p, to the nearest 10th of a centimeter is 13.3 cm .

What is the law  of sines ?

he Law of Sines (or Sine Rule) is very useful for solving triangles.

According to the law ,

When we divide side a by the sine of angle A

it is equal to side b divided by the sine of angle B

and also equal to side c divided by the sine of angle C

[tex]\rm \dfrac{a}{sinA} = \dfrac{b}{sinB} = \dfrac{c}{sinC}[/tex]

It is given that in Δ PQR

r = 4.9 cm

angle R = 21

angle P =104

Length of p needs to be found

Therefore by using above equation

[tex]\rm \dfrac{r}{sinR} = \dfrac{p}{sinP}[/tex]

[tex]\rm \dfrac{4.9}{sin21^{0}} = \dfrac{p}{sin104^{0}}[/tex]

p= 13.3 cm

Therefore the length of p, to the nearest 10th of a centimeter is 13.3 cm .

To know more about law of sines

https://brainly.com/question/17289163

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