Westonci.ca is your trusted source for accurate answers to all your questions. Join our community and start learning today! Get quick and reliable solutions to your questions from a community of experienced experts on our platform. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.
Sagot :
Answer:
You use the fact that 1 mole of any substance contains exactly 6.022⋅1023 atoms or molecules of that substance - this is known as Avogadro's number. In your case, 1 mole of gold will have exactly 6.022⋅1023 atoms of gold.
So it would be answer 3690 atoms or 3.60x1025
The number of atoms of gold in 591 g has been [tex]1.81\;\times\;10^2^4[/tex] atoms. Thus, option B is correct.
The number of atoms in a mole of sample has been given by the Avogadro's law. According to the law, one mole of a substance has been equivalent to [tex]6.023\;\times\;10^2^3[/tex] atoms.
The mole of sample has been given as the mass of sample with respect to the molar mass. Moles have been expressed as:
[tex]\rm Moles=\dfrac{Mass}{Molar\;mass}[/tex]
Number of atoms in a sample
The mass of gold has been 591 g
The molar mass of gold has been 197 g.
Substituting the values for moles of gold:
[tex]\rm Moles=\dfrac{591 }{197 } \\Moles=3\;moles[/tex]
The available moles of sample has been 3 moles.
The number of atoms has been given by:
[tex]\rm 1\;moles=6.023\;\times\;10^2^3\;atoms\\3\;moles=6.023\;\times\;10^2^3\;\times\;3\;atoms\\3\;moles=18.1\;\times\;10^2^3\;atoms\\3\;moles=1.81\;\times\;10^2^4\;atoms[/tex]
The number of atoms of gold in 591 g has been [tex]1.81\;\times\;10^2^4[/tex] atoms. Thus, option B is correct.
Learn more about number of atoms, here:
https://brainly.com/question/4206478
Thanks for using our service. We aim to provide the most accurate answers for all your queries. Visit us again for more insights. Thank you for visiting. Our goal is to provide the most accurate answers for all your informational needs. Come back soon. Thank you for visiting Westonci.ca, your go-to source for reliable answers. Come back soon for more expert insights.