neelanhussain88
Answered

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how do you solve these kinds of equations? (3x+5) (3x+5)

Sagot :

crystivia

Answer:

-5/3

Step-by-step explanation:

(3x+5)(3x+5) is the factored form of the quadratic: 9x^2+30x+25

In equation form, it will be 9x^2+30x+25 = 0 so we have:

(3x+5)(3x+5) = 0

To solve these types of equations, we find the roots. Since the product of these numbers is 0, (3x+5) has to be equal to 0.

3x + 5 = 0

Subtract 5

3x = -5

Divide by 3

x = -5/3

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