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Sagot :
Answer:
Gabby's momentum before the collision is 202 kg·m/s
Explanation:
The given parameters of the motion of the people playing football in the park are;
The interaction of Marie and Gabby when they go for the interception = Collide
The total momentum of Marie ang Gabby after the collision, [tex]\Sigma P_{final}[/tex] = 382 kg·m/s
The initial momentum of Marie, P₁ = 180 kg·m/s
By the law conservation of conservation of linear momentum, we have;
The total initial momentum before the collision, [tex]\Sigma P_{initial}[/tex] = The total momentum after the collision, [tex]\Sigma P_{final}[/tex]
The total initial momentum before the collision, [tex]\Sigma P_{initial}[/tex] = Marie's momentum before the collision, P₁ + Gabby's momentum before the collision, P₂
∴ [tex]\Sigma P_{initial}[/tex] = P₁ + P₂ = 180 kg·m/s + P₂
From which we have;
[tex]\Sigma P_{initial}[/tex] = 180 kg·m/s + P₂ = [tex]\Sigma P_{final}[/tex] = 382 kg·m/s
∴ 180 kg·m/s + P₂ = 382 kg·m/s
P₂ = 382 kg·m/s - 180 kg·m/s = 202 kg·m/s
P₂ = 202 kg·m/s
Gabby's momentum before the collision, P₂ = 202 kg·m/s.
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