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Sagot :
Mass of LiOH= 23.95 grams ≈ 24 g
Further explanation
Given
1 mole of lithium hydroxide (LiOH)
Required
Mass of LiOH
Solution
The mole is the number of particles contained in a substance
1 mol = 6.02.10²³
Moles can also be determined from the amount of substance mass and its molar mass
n = mass : molar mass
Input the value :
mass = n x molar mass
mass = 1 mole x 23,95 g/mol
mass = 23.95 grams ≈ 24 g
The mass of 1 mole LiOH has been 24 g. Thus, option D is correct.
The mass of a compound present in a mole of sample has been equivalent to the molar mass of the compound. The molar mass of the compound has been the sum of the constituent in a formula unit.
The molar mass of lithium hydroxide (mwt) has been given as:
[tex]mwt=m_L_i\;+\;m_O\;+\;m_H[/tex]
Where, the mass of Li is [tex]m_L_i=6.941\;\rm g[/tex]
The mass of oxygen is [tex]m_O=16\;\rm g[/tex]
The mass of hydrogen is [tex]m_H=1\;\rm g[/tex]
Substituting the values for molar mass (mwt) of LiOH:
[tex]mwt=6.941\;+\;16\;+\;1\;\text g\\mwt=23.941\;\text g\\mwt=24\;\text g[/tex]
The molar mass of LiOH has been 24 g.
The molar mass has been equivalent to the mass of 1 mole of sample. Thus, the mass of 1 mole LiOH has been 24 g. Thus, option D is correct.
For more information about mass of mole, refer to the link:
https://brainly.com/question/1370888
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