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A chemical reaction yields 1 mole of lithium hydroxide (LiOH). How many grams of
lithium hydroxide are present?
3 g
48 g
728
24 g


Sagot :

Mass of LiOH= 23.95 grams ≈ 24 g

Further explanation

Given

1 mole of lithium hydroxide (LiOH)

Required

Mass of LiOH

Solution

The mole is the number of particles contained in a substance

1 mol = 6.02.10²³

Moles can also be determined from the amount of substance mass and its molar mass

n = mass : molar mass

Input the value :

mass = n x molar mass

mass = 1 mole x 23,95 g/mol

mass = 23.95 grams ≈ 24 g

 

The mass of 1 mole LiOH has been 24 g. Thus, option D is correct.

The mass of a compound present in a mole of sample has been equivalent to the molar mass of the compound. The molar mass of the compound has been the sum of the constituent in a formula unit.

The molar mass of lithium hydroxide (mwt) has been given as:

[tex]mwt=m_L_i\;+\;m_O\;+\;m_H[/tex]

Where, the mass of Li is [tex]m_L_i=6.941\;\rm g[/tex]

The mass of oxygen is [tex]m_O=16\;\rm g[/tex]

The mass of hydrogen is [tex]m_H=1\;\rm g[/tex]

Substituting the values for molar mass (mwt) of LiOH:

[tex]mwt=6.941\;+\;16\;+\;1\;\text g\\mwt=23.941\;\text g\\mwt=24\;\text g[/tex]

The molar mass of LiOH has been 24 g.

The molar mass has been equivalent to the mass of 1 mole of sample. Thus, the mass of 1 mole LiOH has been 24 g. Thus, option D is correct.

For more information about mass of mole, refer to the link:

https://brainly.com/question/1370888

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