Welcome to Westonci.ca, where curiosity meets expertise. Ask any question and receive fast, accurate answers from our knowledgeable community. Experience the convenience of finding accurate answers to your questions from knowledgeable professionals on our platform. Experience the convenience of finding accurate answers to your questions from knowledgeable experts on our platform.

A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution. How many of each should be used ?

Sagot :

Answer:

The number of liters of 25% acid solution = x = 160 liters

The number of liters of 40% acid solution = y = 80 liters

Step-by-step explanation:

Let us represent:

The number of liters of 25% acid solution = x

The number of liters of 40% acid solution = y

Our system of Equations =

x + y = 240 liters....... Equation 1

x = 240 - y

A 25% acid solution must be added to a 40% solution to get 240 liters of 30% acid solution.

25% × x + 40% × y = 240 liters × 30%

0.25x+ 0.4y = 72...... Equation 2

We substitute 240 - y for x in Equation 2

0.25(240 - y)+ 0.4y = 72

60 - 0.25y + 0.4y = 72

Collect like terms

- 0.25y + 0.4y = 72 - 60

0.15y = 12

y = 12/0.15

y = 80 Liters

Solving for x

x = 240 - y

x = 240 liters - 80 Liters

x = 160 liters

Therefore,

The number of liters of 25% acid solution = x = 160 liters

The number of liters of 40% acid solution = y = 80 liters