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Sagot :
Answer:
Minimum price of the coffee = $ 4.1
Maximum price of the coffee = $ 5.68
Step-by-step explanation:
Let us assume
The minimum price of the coffee = $x
As given , the prices of this can of coffee vary by as much as $1.58.
⇒ Maximum price of the coffee will be = $ x+1.58
Now, as given , The average price of coffee = $4.89
⇒[tex]\frac{Maximum + Minimum}{2}[/tex] = $4.89
⇒ Maximum + Minimum = 9.78
⇒x + 1.58 + x = 9.78
⇒2x + 1.58 = 9.78
⇒2x = 9.78 - 1.58
⇒2x = 8.2
⇒x = [tex]\frac{8.2}{2}[/tex] = 4.1
∴ we get
Minimum price of the coffee = x = $ 4.1
Maximum price of the coffee = x + 1.58 = $ 4.1 + 1.58 = $ 5.68
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