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Find the perimeter of a rectangle with sides 3x + 6 and -2x -8​

Sagot :

Answer:

2x - 4

Step-by-step explanation:

2(3x + 6) = 6x + 12

2(-2x - 8) = -4x -16

6x + 12 - 4x - 16 = 2x - 4

absor201

Answer:

The perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:

[tex]P = 2x - 4[/tex]

Step-by-step explanation:

We know that the perimeter of a rectangle of length 'l' and width 'w' is given by the formula

  • P = 2(length + width)

Given the sides of a rectangle

  • 3x + 6
  • -2x - 8​

As the opposite sides of a rectangle are congruent.

Therefore, we conclude that the Perimeter of a rectangle can be determined using the formula

[tex]\:P\:=\:2\left(3x\:+\:6\:+\:\left(-2x\:-\:8\right)\right)[/tex]

    [tex]=2\left(3x+6-2x-8\right)[/tex]

    [tex]=2\left(x-2\right)[/tex]

     [tex]=2x-4[/tex]

Therefore, the perimeter of a rectangle with sides 3x + 6 and -2x - 8​ will be:

[tex]P = 2x - 4[/tex]

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