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Sagot :
Answer:
In your equation y=2x+3 and you used 2 [from your point (2,5) ] as the value of x, then y=2(2)+3=7.
now if you plotted this, that point would be (2,7), not (2,5).
So (2,5) is not the solution.
(2, 5) is not a solution of the linear equation [tex]y = 2\cdot x + 3[/tex].
Let be linear equation [tex]y = 2\cdot x + 3[/tex], if we know that [tex](x,y) = (2, 5)[/tex] and we need to check is [tex]2\cdot x + 3 = 5[/tex] by algebraic means, that is, we solve for [tex]x[/tex]:
[tex]2\cdot x + 3 = 5[/tex]
[tex]2\cdot x = 2[/tex]
[tex]x = 1[/tex]
Hence, we conclude that (2, 5) is not a solution of the linear equation [tex]y = 2\cdot x + 3[/tex].
We kindly invite to check this question on linear functions: https://brainly.com/question/17088086
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