Answered

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álgebra II. Help please...

Álgebra II Help Please class=

Sagot :

Yuqiao

Answer:

See below

Step-by-step explanation:

The domain of [tex]f[/tex] is non-negative real numbers, and the domain of [tex]g[/tex] is real numbers.

[tex](f\circ g)(x) = 2\sqrt{2}|x|^5[/tex] (I skipped calculation details), so [tex](f\circ g)(9) = 2 \sqrt{2} \cdot 9^5[/tex].

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