Answered

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10 points
A 61.0 kg box is sitting at rest. In order to change the box's state of
motion, Jamie must apply 75.1 Newtons of force on the box. Which of the
following represents a possible value for the force of static friction when
Jamie applied 75.1 Newtons of force on the box? (**hint- you do not need
to do math for this problem) *
A. 71.9 N
B. 75.1 N
C. 85.3 N
D. 133 N

Sagot :

eryndun1049
The answer is B tell me if I am wrong.
abidemiokin

A possible value for the force of static friction when  Jamie applied 75.1 Newtons of force on the box is 75.1N. Option B is correct.

For the box sitting on a horizontal surface, the formula for calculating the force on the box along the horizontal based on Newton's law is expressed as;

  • [tex]\sum F_x=ma_x[/tex]

Since the forces acting along the horizontal are the frictional force and moving force, the formula above will become;

  • [tex]F_m-F_f=ma_x[/tex]

Since the body is static, hence [tex]a_x=0m/s^2[/tex], the equation becomes;

  • [tex]F_m-F_f=m(0)\\F_m-F_f=0\\F_m=F_f[/tex]

Given the force Jamie apply on the box to be 75.1Newtons, this shows that the moving force is 75.1N. Hence;

  • [tex]F_m =F_f=75.1N[/tex]

Hence a possible value for the force of static friction when  Jamie applied 75.1 Newtons of force on the box is 75.1N

Learn more on friction here: https://brainly.com/question/11435018

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