Answered

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What is the equation of the line perpendicular to Y= 1/2x +6 that passes through the point (4,1)

Sagot :

s1m1

Answer:

Step-by-step explanation:

y= mx+b is the general equation where m is the slope

y= 1/2 x +6 has the slope 1/2

perpendicular lines have the slope negative reciprocal

so the slope of the ⊥ line is -2

y = -x +b , yet for point (4, 1) the x=4 and y =1

1= -4 +b so b= 5

the equation of the ⊥ line is y= -2x+5

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