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Graph the line with a slope of 2/3 that contains the point (−3,−5)

Sagot :

irjt

Answer:

Step-by-step explanation:

So for the given information, it would be easiest to use slope-intercept form, which is y=mx + b, where m is the slope and b is the y-intercept.

We can plug in 2/3 for the slope, because we are given that.

y=2/3x + b.

To find the y-intercept, plug in the given point for x and y and solve for b.

-5 = 2/3 · (-3) + b

-5 = -2 + b

b = -3

So now we have the complete equation of the line.

y = 2/3x -3

Now to graphing.

We can put the y-intercept, (0, -3), and the given point, (-3, -5) on a graph.

View image irjt
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