Answered

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How far will a force of 6 x 10^3N stretch a spring with spring constant 3 x 10^4 Nm-1 ?

Sagot :

ohiekulous

Answer:

0.2m

Explanation:

F = 6 x 10^3N

k = 3 x 10^4 Nm-1

x = ?

from Hooke's law, F = kx

x = F/k = 6 x 10^3 ÷ 3 x 10^4 = 0.2m

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