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5. A mountain has a base and peak that are inaccessible. At point A, the angle of elevation of the peak is
30°. One kilometer closer to the mountain, at point C, the angle of elevation of 35º. Find the height
PB of the mountain.

Sagot :

Answer:

1.366km

Step-by-step explanation:

The height of the mountain is [tex]3.34Km[/tex]

Right angle triangle:

A diagram of right angle triangle PBA is attached below which describe the situation as given in the question.

Let us consider that H represent the height of mountain.

Angle of elevation at point A and C shown in the diagram.

Apply tan function in triangle CBP.

            [tex]tan(35)=\frac{H}{x} \\\\H=xtan(35)=0.7x.........(1)[/tex]

Apply tan function in triangle ABP.

           [tex]tan(30)=\frac{H}{x+1}\\ \\(x+1)tan(30)=H\\\\(x+1)=\sqrt{3}H\\ \\x=\sqrt{3}H-1........(2)[/tex]

Substituting the value of equation 2 into equation 1.

      [tex]H=0.7(\sqrt{3}H-1)\\\\H=1.21H-0.7\\\\0.21H=0.7\\\\H=0.7/0.21=3.34Km[/tex]

Hence, The height of the mountain is [tex]3.34Km[/tex]

Learn more about the right angle triangle here:

https://brainly.com/question/64787

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