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The average value of a function f on [a, b]
always lies between f(a) and f(b). Justify your answer.


Sagot :

Answer:

False

Step-by-step explanation:

A parabola is a good example of proving this false, but more specifically is the graph of sin x on the interval [0, pi]. sin 0 = sin pi = 0, but the average value of sin x on this interval is greater than 0.