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A pendulum has a period of 6.98s. Calculate the length of the pendulum. Use
9.8m/s^2 for gravity. *

Sagot :

Lanuel

Answer:

Length, l = 0.126 meters.

Explanation:

Given the following data;

Period = 6.98s

Acceleration due to gravity, g = 9.8m/s²

To find the length, l;

[tex] Period, T = 2 \pi \sqrt {lg} [/tex]

Substituting into the equation, we have;

[tex] 6.98 = 2*3.142 \sqrt {l*9.8} [/tex]

[tex] 6.98 = 6.284 \sqrt {9.8l} [/tex]

[tex] \frac {6.98}{6.284} = \sqrt {9.8l} [/tex]

[tex] 1.1108 = \sqrt {9.8l} [/tex]

Taking the square of both sides

[tex] 1.1108^{2} = 9.8l [/tex]

[tex] 1.2339 = 9.8l [/tex]

[tex] l = \frac {1.2339}{9.8} [/tex]

Length, l = 0.126m.

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