Answer:
[tex]4jkl[/tex]
Step-by-step explanation:
[tex] \frac{(64 {j}^{4} {k}^{8} {l}^{2}) ^ \frac{1}{2} }{(8 {j}^{3} {k}^{9}) ^{ \frac{1}{3} } } \\ \\ \frac{( {2}^{6} \times {j}^{4} \times {k}^{8} \times {l}^{2} ) ^{ \frac{1}{2} } }{ ({2}^{3} \times {j}^{3} \times {k}^{9}) ^{ \frac{1}{3} } } \\ \\ \frac{ {2}^{6 \times \frac{1}{2} } \times {j}^{4 \times \frac{1}{2} } \times {k}^{8 \times \frac{1}{2} } \times {l}^{2 \times \frac{1}{2} } }{ {2}^{3 \times \frac{1}{3} } \times {j}^{3 \times \frac{1}{3} } \times {k}^{9 \times \frac{1}{3} } } \\ \\ \frac{ {2}^{3} \times {j}^{2} \times {k}^{4} \times l}{2 \times j \times {k}^{3} } \\ \\ {2}^{(3 - 1)} \times {j}^{(2 - 1)} \times {k}^{(4 - 3)} \times l \\ \\ {2}^{2} \times j \times k \times l \\ \\ = 4jkl[/tex]
Hope this helps you.
Let me know if you have any other questions :-):-)
