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solve similar triangles advanced Pleasee help! TIA

Solve Similar Triangles Advanced Pleasee Help TIA class=

Sagot :

MrRoyal

Answer:

[tex]x = 3.5[/tex]

Step-by-step explanation:

Given

Attached Triangle

Required

Find x

To solve for x, we make use of the following equivalent ratios:

[tex]CB : BA = ED : DA[/tex]

Where:

[tex]CB = 2[/tex]

[tex]BA = 4[/tex]

[tex]ED = x[/tex]

[tex]DA = 3 + 4 = 7[/tex]

So, the expression becomes:

[tex]CB : BA = ED : DA[/tex]

[tex]2 : 4 = x : 7[/tex]

Express as fraction

[tex]\frac{2 }{ 4} = \frac{x }{ 7}[/tex]

Multiply both sides by 7

[tex]7*\frac{2 }{ 4} = \frac{x }{ 7}*7[/tex]

[tex]7*\frac{2 }{ 4} = x[/tex]

[tex]\frac{7*2 }{ 4} = x[/tex]

[tex]\frac{14}{4} = x[/tex]

[tex]3.5 = x[/tex]

[tex]x = 3.5[/tex]

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