Answer:
Step-by-step explanation:
Let the transmitter be located at (0,0)
The equation for its effective coverage area will be a circle centered at (0,0) with a radius of 49.
So....the equation is
[tex]x^2 + y^2 = 49^2[/tex]
[tex]x^2 + y^2 = 2401[/tex]
Let the point 67 miles north of the transmitter be (0, 67)
Let the point 63 miles east of the transmitter be (63, 0)
The line connecting these (the line of travel) will have a slope of
[67 - 0] / [ 0 - 63] = -67/63
The equation of this line will be: y = (-67/63)x + 67
The signal will be received between the points:
(21.681, 43.942) and (45.192, 18.938)
The distance between these points is
[tex]\sqrt{[ ( 45.192 - 21.681)^2 + ( 43.942 - 18.938)^2 ] } = 34.322 miles[/tex] (1)
The distance between (0, 63) and (67, 0)
[tex]\sqrt{[ ( 63)^2 + ( 67)^2 ] }=91.97miles[/tex] (2)
So....you will receive the signal using (1)/ (2)
(34.322 / 91.97) x 100 ≈ 37% of the drive
