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Sagot :
Given:
The compound inequality is
[tex]9<3x+6\leq 15[/tex]
To find:
The solution for the given compound inequality in interval notation.
Solution:
We have,
[tex]9<3x+6\leq 15[/tex]
Subtracting 6 from each side, we get
[tex]9-6<3x+6-6\leq 15-6[/tex]
[tex]3<3x\leq 9[/tex]
Divide each side by 3.
[tex]\dfrac{3}{3}<\dfrac{3x}{3}\leq \dfrac{9}{3}[/tex]
[tex]1<x\leq 3[/tex]
Here, 1 is not included in the solution set and 3 is included in the solution set.
Therefore, the solution in interval notation is (1,3].
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