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Sagot :
Answer:
The presents age of the mom is 42 years old, and of the son is 27 years old.
Step-by-step explanation:
This question can be solved using a system of equations.
I am going to say that:
The mothers age is x.
The son's age is y.
12 years ago, a mother was twice as old as her son.
This means that:
[tex]x - 12 = 2(y - 12)[/tex]
[tex]x = 2y - 24 + 12[/tex]
[tex]x = 2y - 12[/tex]
Their present age are in the ratio of 14:9.
This means that:
[tex]\frac{x}{y} = \frac{14}{9}[/tex]
[tex]14y = 9x[/tex]
Since [tex]x = 2y - 12[/tex]
[tex]14y = 9(2y - 12)[/tex]
[tex]18y - 108 = 14y[/tex]
[tex]4y = 108[/tex]
[tex]y = \frac{108}{4}[/tex]
[tex]y = 27[/tex]
[tex]x = 2*27 - 12 = 54 - 12 = 42[/tex]
The presents age of the mom is 42 years old, and of the son is 27 years old.
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