Westonci.ca offers fast, accurate answers to your questions. Join our community and get the insights you need now. Join our Q&A platform to connect with experts dedicated to providing accurate answers to your questions in various fields. Explore comprehensive solutions to your questions from a wide range of professionals on our user-friendly platform.

amy borrowed money from the lending company at 6% interest if she paid an interest of php450.00 after 19months how much money did she borrow​

Sagot :

Answer:

She borrowed php4737.00.

Step-by-step explanation:

This is a simple interest problem.

The simple interest formula is given by:

[tex]E = P*I*t[/tex]

In which E is the amount of interest earned, P is the principal(the initial amount of money), I is the interest rate(yearly, as a decimal) and t is the time.

After t years, the total amount of money is:

[tex]T = E + P[/tex]

6% interest:

This means that [tex]I = 0.06[/tex]

19 months:

An year has 12 months, so [tex]t = \frac{19}{12} = 1.5833[/tex]

She paid an interest of php 450. How much money did she borrow​

This is P when [tex]E = 450[/tex]. So

[tex]E = P*I*t[/tex]

[tex]450 = P*0.06*1.5833[/tex]

[tex]P = \frac{450}{0.06*1.5833}[/tex]

[tex]P = 4737[/tex]

She borrowed php4737.00.

Thanks for stopping by. We strive to provide the best answers for all your questions. See you again soon. Your visit means a lot to us. Don't hesitate to return for more reliable answers to any questions you may have. Find reliable answers at Westonci.ca. Visit us again for the latest updates and expert advice.