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A small town has two local high schools. High School A currently has 850 students
and is projected to grow by 35 students each year. High School B currently has 700
students and is projected to grow by 60 students each year. Let A represent the
number of students in High School A int years, and let B represent the number of
students in High School B after t years. Write an equation for each situation, in terms
of t, and determine after how many years, t, the number of students in both high
schools would be the same.

Sagot :

LanceLongFei

Answer:

For High School A, let [tex]S_A(t)[/tex] denote the number of students after [tex]t[/tex] years. Define [tex]S_B(t)[/tex] analogously.

Then [tex]S_A(t) = 850 + 35t[/tex] and [tex]S_B(t) = 700 + 60t[/tex].

After 6 years the number of students in both high schools would be the same.

Step-by-step explanation:

For High School A, let [tex]S_A(t)[/tex] denote the number of students after [tex]t[/tex] years. Define [tex]S_B(t)[/tex] analogously.

Since we start out at 850 students at High School A and it is growing by 35 students every year, we must have that [tex]S_A(t) = 850 + 35t[/tex].

Since we start out at 700 students at High School B and it is growing by 60 students every year, we must have that [tex]S_B(t) = 700 + 60t[/tex].

Setting the two equations equal to each other, we see that [tex]850+35t=700+60t\\850-700=60t-35t\\25t=150\\t=6[/tex]

So after 6 years the number of students in both high schools would be the same.

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