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Sagot :
Answer:
For High School A, let [tex]S_A(t)[/tex] denote the number of students after [tex]t[/tex] years. Define [tex]S_B(t)[/tex] analogously.
Then [tex]S_A(t) = 850 + 35t[/tex] and [tex]S_B(t) = 700 + 60t[/tex].
After 6 years the number of students in both high schools would be the same.
Step-by-step explanation:
For High School A, let [tex]S_A(t)[/tex] denote the number of students after [tex]t[/tex] years. Define [tex]S_B(t)[/tex] analogously.
Since we start out at 850 students at High School A and it is growing by 35 students every year, we must have that [tex]S_A(t) = 850 + 35t[/tex].
Since we start out at 700 students at High School B and it is growing by 60 students every year, we must have that [tex]S_B(t) = 700 + 60t[/tex].
Setting the two equations equal to each other, we see that [tex]850+35t=700+60t\\850-700=60t-35t\\25t=150\\t=6[/tex]
So after 6 years the number of students in both high schools would be the same.
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