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Please help!!!!

If f(1) = 2 and f(n+1) = f(n)^2 – 3 then find the value of f(3).

Sagot :

Answer:

The value of f(3) is -2.

Step-by-step explanation:

This is a recursive function. So

[tex]f(1) = 2[/tex]

Now, we find f(2) in function of f(1). So

[tex]f(1+1) = f(1)^2 - 3[/tex]

[tex]f(2) = f(1)^2 - 3 = 2^2 - 3 = 1[/tex]

Now, with f(2), we can find the value of f(3).

[tex]f(2+1) = f(2)^2 - 3[/tex]

[tex]f(3) = f(2)^2 - 3 = 1^2 - 3 = -2[/tex]

The value of f(3) is -2.