gangelucci17
Answered

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If the spring constant is 12.6N/m and a spring is stretched by 0.25m, how much force has been applied?

Sagot :

Answer:

3.15N

Explanation:

We use this equation:

F= k∆x

Where ∆x refers to the amount or stretch or compression and k is the spring constant.

F = force

k = spring constant

∆x = change in length of spring

To find the value of F:

F= k∆x

F= 12.6x0.25

F= 3.15N

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