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Sagot :
Given:
The points (0,2), (1,3), (2,6), and (3,11) are on the graph of a function.
To find:
The function.
Solution:
In option A,
[tex]h(x)=x^2+2[/tex]
Putting x=0, 1, 2, 3 respectively, we get
[tex]h(0)=(0)^2+2=2[/tex]
[tex]h(1)=(1)^2+2=3[/tex]
[tex]h(2)=(2)^2+2=6[/tex]
[tex]h(3)=(3)^2+2=11[/tex]
The function passes through the points (0,2), (1,3), (2,6), and (3,11). So, [tex]h(x)=x^2+2[/tex] is the required function.
In option B,
[tex]h(x)=0.5x^2+1.5[/tex]
At x=0,
[tex]h(0)=0.5(0)^2+1.5=1.5\neq 2[/tex]
So, option B is incorrect.
In option C,
[tex]h(x)=2x^2[/tex]
At x=0,
[tex]h(0)=2(0)^2=0\neq 2[/tex]
So, option C is incorrect.
In option D,
[tex]h(x)=x+2[/tex]
At x=2,
[tex]h(2)=(2)+2=4\neq 6[/tex]
So, option D is incorrect.
Therefore, the correct option is A.
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