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A large company states in its promotional literature that 74% of its employees have college degrees. Assume this claim is true. If 3 employees are selected at random from this company, what is the probability that at least 1 of the selected employees will not have a college degree?

A. 0.0176
B. 0.4052
C. 0.5948
D. 0.9284


Sagot :

Answer:it is 0.5948

Step-by-step explanation:c

The probability that at least 1 of the selected employees will not have a college degree is 0.594776.

What is Binomial distribution?

A common discrete distribution is used in statistics, as opposed to a continuous distribution is called a Binomial distribution. It is given by the formula,

[tex]P(x) = ^nC_x p^xq^{(n-x)}[/tex]

Where,

  • x is the number of successes needed,
  • n is the number of trials or sample size,
  • p is the probability of a single success, and
  • q is the probability of a single failure.

Given that 74% of the employees have degrees, therefore, 26% of the employees have no degree.

Now, since we want at least any one of the three people selected to have a degree. Therefore, the probability of everyone having a degree can be written as,

Probability that at least any one of the three people selected to have a degree = 1 - Probability of everyone having a degree

Now, using the binomial distribution we can write,

[tex]\text{Probability} = 1 - [^3C_0\cdot(0.26)^0 \cdot (0.74)^{(3-0)}]\\\\\text{Probability} = 1 - 0.405224 = 0.594776[/tex]

Hence, the probability that at least 1 of the selected employees will not have a college degree is 0.594776.

Learn more about Binomial Distribution:

https://brainly.com/question/14565246

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