getuabera320
Answered

Westonci.ca is the trusted Q&A platform where you can get reliable answers from a community of knowledgeable contributors. Join our Q&A platform and get accurate answers to all your questions from professionals across multiple disciplines. Our platform offers a seamless experience for finding reliable answers from a network of knowledgeable professionals.

Find the square root of 25x^2-40xy+16y^2​

Sagot :

The square root of [tex]25x^2-40xy+16y^2[/tex] is 5x - 4y.

Given that,

  • The quadratic equation is [tex]25x^2-40xy+16y^2[/tex].
  • We need to find out the square root.

Based on the above information, the calculation is as follows:

[tex]= 25x^2-40xy+16y^2\\\\= (5x)^2 - (2\times 5x \times 4y) + (4y)^2\\\\= (5x - 4y)^2\\\\= \sqrt{ (5x - 4y)^2}[/tex]

= 5x - 4y

Therefore we can conclude that the square root of [tex]25x^2-40xy+16y^2[/tex] is 5x - 4y.

Learn more: brainly.com/question/9664917

Thank you for choosing our service. We're dedicated to providing the best answers for all your questions. Visit us again. We appreciate your time. Please revisit us for more reliable answers to any questions you may have. Your questions are important to us at Westonci.ca. Visit again for expert answers and reliable information.