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The point M is the midpoint of LN where M(-12, 6) and N (-2,-5).
What are the coordinates of point L?


Sagot :

Answer:

The coordinates of point L are:

(x₁, y₁) = (-22, 17)

Step-by-step explanation:

We know that the Midpoint Formula is given by:

[tex]\left(x,\:y\right)=\left(\frac{x_2+x_1}{2},\:\:\frac{y_2+y_1}{2}\right)[/tex]

In our case:

M(-12, 6) is the midpoint. Thus,

(x, y)  = (-12, 6)

N(-2, -5) is the second point, Thus,

(x₂, y₂) = (-2,-5)

We have to determine the coordinates of point L.

Let (x₁, y₁)  be the coordinates of point L.

substituting (x, y)  = (-12, 6), (x₂, y₂) = (-2,-5) in the Midpoint Formula

[tex]\left(-12,\:6\right)=\left(\frac{-2+x_1}{2},\:\:\frac{-5+y_1}{2}\right)[/tex]

Determining the x₁ coordinate of the point L

[tex]\frac{-2+x_1}{2}=-12[/tex]

[tex]-2+x_1=-24[/tex]

Add 2 to both sides

[tex]-2+x_1+2=-24+2[/tex]

Simplify

[tex]x_1=-22[/tex]

Determining the y₁ coordinate of the point L

[tex]\frac{-5+y_1}{2}=6[/tex]

[tex]-5+y_1=12[/tex]

Add 5 to both sides

[tex]-5+y_1+5=12+5[/tex]

Simplify

[tex]y_1=17\:\:\:[/tex]

Therefore, the coordinates of point L are:

(x₁, y₁) = (-22, 17)

Answer:

the person up top is correct